C Puzzles

yet another place for C puzzles

Saturday, December 16, 2006

loop 20 times


int main()
{
        int i, n = 20;
        for (i = 0; i < n; i--)
                printf("*");
 return 0;
}

Change/add only one character and print '*' exactly 20 times.
(there are atleast 3 solutions to this problem :-)

I got TWO:
1.for (i = 0; i < n--)
2.for (i = 0; i + n; i--)

posted by yetanother.softwarejunk # 8:19 AM

Comments:

3. for (i = 0; -i < n; i--)

Hassan Shaik

# posted by

Anonymous : 5:44 PM, December 19, 2006

1 for(i=0;-i * n;i--)
2 for(i=0;i+n;i--)
3 for(i=0;i * n;n--)
Note : replace * with less than sign ... i was unable to give less than sign as comments are in html

Rahul Ugale(Calsoft,Pune)

# posted by

Anonymous : 9:02 PM, December 29, 2006

wow hard in beginning,but easy when answers are found

# posted by

Anonymous : 9:56 AM, August 28, 2007

int i, n = 20;
for (i = 0; i < n; i++)
printf("*");

# posted by

Sreyasee Das Bhattacharjee : 6:11 PM, June 11, 2008

right answers:
"for(i=0; i+n; i--)"
for(i=0; i< n; n--)
for(i=0; -i< n; i--)

# posted by

Anonymous : 12:32 PM, July 04, 2008

Would someone mind explaining the for(i=0;i+n;i--) solution? I got the other 2 on my own, but I am still a beginner at C and do not get what is going on here. Thanks

# posted by

Keith : 2:23 AM, December 20, 2008

Keith,

after 20th iteration, i+n == -20 + 20 == ZERO.
it terminates the loop.

# posted by

yetanother.softwarejunk : 9:50 AM, December 22, 2008

C Puzzles

Saturday, December 16, 2006

loop 20 times

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